Giải bpt
1, \(\left|4x-3\right|=\left|4x+1\right|\)
2, \(\left|7x-1\right|=\left|7x+3\right|\)
3, \(\left|x+2\right|-3\left|x-1\right|< 2\left(x+4\right)\)
4, \(\left|x+5\right|-\left|x-7\right|< 4\)
Những câu hỏi liên quan
a) \(^{ }\left(7x+4\right)^2-\left(7x-4\right)\left(7x+4\right)\)
b) \(^{ }8\left(x-2\right)-3\left(x^2-4x-5\right)-5x^2\)
c) \(^{^{ }}\left(x+1\right)^3-\left(x-1\right)\left(x^2+x+1\right)-3x\left(x+1\right)\)
a: Ta có: \(\left(7x+4\right)^2-\left(7x-4\right)\left(7x+4\right)\)
\(=\left(7x+4\right)\left(7x+4-7x+4\right)\)
\(=8\left(7x+4\right)\)
=56x+32
b: Ta có: \(8\left(x-2\right)^2-3\left(x^2-4x-5\right)-5x^2\)
\(=8x^2-32x+32-3x^2+12x+15-5x^2\)
\(=-20x+47\)
c: Ta có: \(\left(x+1\right)^3-\left(x-1\right)\left(x^2+x+1\right)-3x\left(x+1\right)\)
\(=x^3+3x^2+3x+1-x^3+1-3x^2-3x\)
=2
Đúng 1
Bình luận (1)
Giải phương trình:
1, left(x^2+x+1right)left(x^4+2x^3+7x^2+26x+37right)5left(x+3right)^3
2, left(x+1right)^3+left(x+3right)^3+6left(x+1right)left(x+7right)left(x+3right)8left(x+2right)^3
3, x^3+left(x-1right)^3+3xleft(x-1right)left(x^4+xright)left(2x-1right)^3
4, dfrac{left(x+1right)^3}{3x+1}+dfrac{x^3+5x+2}{x^3+2x+1}x+3
5, dfrac{5x^3+x^2+x+1}{4x^2+1}+dfrac{6left(4x^2+1right)}{x^3+x^2+1}x+7
6, left(x^2-4x+1right)^3+left(8x-x^2+4right)^3+left(x-5right)^3125x^3
Đọc tiếp
Giải phương trình:
1, \(\left(x^2+x+1\right)\left(x^4+2x^3+7x^2+26x+37\right)=5\left(x+3\right)^3\)
2, \(\left(x+1\right)^3+\left(x+3\right)^3+6\left(x+1\right)\left(x+7\right)\left(x+3\right)=8\left(x+2\right)^3\)
3, \(x^3+\left(x-1\right)^3+3x\left(x-1\right)\left(x^4+x\right)=\left(2x-1\right)^3\)
4, \(\dfrac{\left(x+1\right)^3}{3x+1}+\dfrac{x^3+5x+2}{x^3+2x+1}=x+3\)
5, \(\dfrac{5x^3+x^2+x+1}{4x^2+1}+\dfrac{6\left(4x^2+1\right)}{x^3+x^2+1}=x+7\)
6, \(\left(x^2-4x+1\right)^3+\left(8x-x^2+4\right)^3+\left(x-5\right)^3=125x^3\)
25 tháng 1 2022 lúc 14:01
1,dfrac{5left(x-1right)+2}{6}-dfrac{7x-1}{4x}dfrac{2left(2x+1right)}{7}-52,dfrac{3left(x-3right)}{4}+dfrac{4x-10,5}{10}dfrac{3
left(x+1right)}{5}+63,dfrac{2left(3x+1right)+1}{4}-5dfrac{2left(3x-1right)}{5}-dfrac{3x+2}{10}Diễn giải ra cho em với ạ!Em cảm ơn
Đọc tiếp
1,\(\dfrac{5\left(x-1\right)+2}{6}\)-\(\dfrac{7x-1}{4x}\)=\(\dfrac{2\left(2x+1\right)}{7}\)-5
2,\(\dfrac{3\left(x-3\right)}{4}\)+\(\dfrac{4x-10,5}{10}\)=\(\dfrac{3 \left(x+1\right)}{5}\)+6
3,\(\dfrac{2\left(3x+1\right)+1}{4}\)-5=\(\dfrac{2\left(3x-1\right)}{5}\)-\(\dfrac{3x+2}{10}\)
Diễn giải ra cho em với ạ!Em cảm ơn
1, bạn xem lại đề
2, 15(x-3) + 8x-21 = 12(x+1) +120
<=> 23x - 66 = 12x + 132
<=> 11x = 198 <=> x = 198/11
3, 10(3x+1) + 5 - 100 = 8(3x-1) - 6x - 4
<=> 30x + 10 - 95 = 18x -12
<=> 12x = 73 <=> x = 73/12
Đúng 4
Bình luận (1)
1.giải các bpt sau
a.\(\left(x-3\right)\left(x+3\right)\ge x^2-7x+1\)
b.\(\dfrac{1,5-x}{5}\ge\dfrac{4x+5}{2}\)
2.giải các pt sau
\(x^3+1=x.\left(x+1\right)\)
Giải pt :
\(\left(x+5\right)^4+\left(x-4\right)^4=\left(2x+1\right)^4\)
\(\left(x^2+3x-4\right)^3+\left(3x^2+7x+4\right)^3=\left(4x^2+10x\right)^3\)
Xem chi tiết
Tính ( rút gọn nếu có thể )
\(3x^4-4x^3+2x\left(x^3-2x^2+7x\right)\)
\(-7x^4+5x^3-x^2\left(-x^2+3x-1\right)\)
\(\left(2x-3\right)\left(x+4\right)+\left(-x+1\right)\left(x-2\right)\)
\(4x\left(x^2-x+3\right)-\left(x-6\right)\left(x-5\right)\)
\(3x^4-4x^3+2x\left(x^3-2x^2+7x\right)\)
\(=3x^4-4x^3+2x^4-4x^3+14x^2\)
\(=5x^4-8x^3+14x^2\)
Đúng 0
Bình luận (0)
3x4 - 4x3 + 2x(x3 - 2x2 + 7x )
= 3x4 - 4x3 + 2x4 _ 4x3 + 14x2
= 5x4 - 8x3 + 14x2
Đúng 0
Bình luận (0)
Tìm x biết : (đề không sai)
1.-4xleft(x-7right)+4xleft(x^2-5right) 28x^2-13
2.left(4x^2-5xright)left(3x+2right)-7xleft(x-7right) left(-4+xright)left(-2x+3right)+12x^3+2x^2
3.left(-4x^2-3right)left(2x+5right)-left(8x-3right) left(-x^2+2right)-5x^2left(x-6right)-3x^2-4
4.left(x-7right)left(x+5right)-left(x-3right)left(x-2right) 15x^2left(x+1right)-left(3x^2-1right) left(5x^2-2right)-21x^2
5.left(x-3right)left(-x+10right)+left(x-8right)left(x+3right) left(5x^2-1right)left(x+3right)-5x^3-15x^2...
Đọc tiếp
Tìm x biết : (đề không sai)
1.\(-4x\left(x-7\right)+4x\left(x^2-5\right)\) \(=28x^2-13\)
2.\(\left(4x^2-5x\right)\left(3x+2\right)-7x\left(x-7\right)\)= \(\left(-4+x\right)\left(-2x+3\right)+12x^3+2x^2\)
3.\(\left(-4x^2-3\right)\left(2x+5\right)-\left(8x-3\right)\) \(\left(-x^2+2\right)=-5x^2\left(x-6\right)-3x^2-4\)
4.\(\left(x-7\right)\left(x+5\right)-\left(x-3\right)\left(x-2\right)\) \(=15x^2\left(x+1\right)-\left(3x^2-1\right)\) \(\left(5x^2-2\right)-21x^2\)
5.\(\left(x-3\right)\left(-x+10\right)+\left(x-8\right)\left(x+3\right)\) \(=\left(5x^2-1\right)\left(x+3\right)-5x^3-15x^2\)
6.\(\left(-2x^2+5\right)\left(-x+3\right)-x^2\left(2x-6\right)\) \(=\left(x-1\right)\left(x+1\right)-\left(x-2\right)\left(x+4\right)\)
Giải các PT sau
a,left(9^2-4right)left(x+1right)left(3x+2right)left(x^2-1right)
b,left(x-1right)^2-1+x^2left(1-xright)left(x+3right)
c,left(x^2-1right)left(x+2right)left(x-3right)left(x-1right)left(x^2-4right)left(x+5right)
d,x^4+x^3+x+10
e,x^3-7x+60
f,x^4-4x^3+12x-90
g,x^5-5x^3+4x0
h,x^4-4x^3+3x^2+4x-40
Đọc tiếp
Giải các PT sau
a,\(\left(9^2-4\right)\left(x+1\right)=\left(3x+2\right)\left(x^2-1\right)\)
b,\(\left(x-1\right)^2-1+x^2=\left(1-x\right)\left(x+3\right)\)
c,\(\left(x^2-1\right)\left(x+2\right)\left(x-3\right)=\left(x-1\right)\left(x^2-4\right)\left(x+5\right)\)
d,\(x^4+x^3+x+1=0\)
e,\(x^3-7x+6=0\)
f,\(x^4-4x^3+12x-9=0\)
g,\(x^5-5x^3+4x=0\)
h,\(x^4-4x^3+3x^2+4x-4=0\)
Giải các phương trình:
\(a.\left(x^2+1\right)\left(x^2-4x+4\right)=0\)
\(b.\left(3x-2\right)\left(\frac{2\left(x+3\right)}{7}-\frac{4x-3}{5}\right)=0\)
\(c.\left(3,3-11x\right)\left(\frac{7x+2}{5}+\frac{2\left(1-3x\right)}{3}\right)=0\)
a)\(\left(x^2+1\right)\left(x^2-4x+4\right)=0\Leftrightarrow\orbr{\begin{cases}x^2+1=0\\x^2-4x+4=0\end{cases}\Rightarrow\orbr{\begin{cases}x^2=-1\left(vn\right)\\\left(x-2\right)^2=0\end{cases}\Rightarrow}x=2}\)
b)\(\left(3x-2\right)\left(\frac{2x+6}{7}-\frac{4x-3}{5}\right)=0\\ \Rightarrow\left(3x-2\right)\left(\frac{10x+30-28x+21}{35}\right)=0\)
\(\Rightarrow\left(3x-2\right)\left(\frac{-18x+51}{35}\right)=0\Rightarrow\orbr{\begin{cases}x=\frac{2}{3}\\x=\frac{17}{6}\end{cases}}\)
c)\(\left(3,3-11x\right)\left(\frac{21x+6+10-30x}{15}\right)=0\Leftrightarrow\orbr{\begin{cases}x=\frac{3}{10}\\x=\frac{16}{9}\end{cases}}\)
Đúng 0
Bình luận (0)